Base | Representation |
---|---|
bin | 100100110000011001111011… |
… | …1100110000101011111111011 |
3 | 1120101202100001222201100120002 |
4 | 1021200303313212011133323 |
5 | 314334121201201130133 |
6 | 3103343311152023215 |
7 | 125046346352221061 |
oct | 11140636746053773 |
9 | 1511670058640502 |
10 | 323312112130043 |
11 | 94020995628063 |
12 | 30318078231b0b |
13 | 10b532804ab8aa |
14 | 59ba565578031 |
15 | 275a153b16ce8 |
hex | 1260cf79857fb |
323312112130043 has 2 divisors, whose sum is σ = 323312112130044. Its totient is φ = 323312112130042.
The previous prime is 323312112130001. The next prime is 323312112130067. The reversal of 323312112130043 is 340031211213323.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 323312112130043 - 214 = 323312112113659 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 323312112129988 and 323312112130015.
It is not a weakly prime, because it can be changed into another prime (323312112130243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 161656056065021 + 161656056065022.
It is an arithmetic number, because the mean of its divisors is an integer number (161656056065022).
Almost surely, 2323312112130043 is an apocalyptic number.
323312112130043 is a deficient number, since it is larger than the sum of its proper divisors (1).
323312112130043 is an equidigital number, since it uses as much as digits as its factorization.
323312112130043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 323312112130043 its reverse (340031211213323), we get a palindrome (663343323343366).
The spelling of 323312112130043 in words is "three hundred twenty-three trillion, three hundred twelve billion, one hundred twelve million, one hundred thirty thousand, forty-three".
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