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324004113301142 = 2162002056650571
BaseRepresentation
bin100100110101011100001011…
…0000101000011111010010110
31120111012111020202000010211202
41021222320112011003322112
5314431440411001114032
63105033233530432502
7125150344654142531
oct11152702605037226
91514174222003752
10324004113301142
119426841120915a
123040a201b92732
1310ba35c2725781
145a01c503dba18
15276d155855d62
hex126ae16143e96

324004113301142 has 4 divisors (see below), whose sum is σ = 486006169951716. Its totient is φ = 162002056650570.

The previous prime is 324004113301027. The next prime is 324004113301199. The reversal of 324004113301142 is 241103311400423.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81001028325284 + ... + 81001028325287.

It is an arithmetic number, because the mean of its divisors is an integer number (121501542487929).

Almost surely, 2324004113301142 is an apocalyptic number.

324004113301142 is a deficient number, since it is larger than the sum of its proper divisors (162002056650574).

324004113301142 is a wasteful number, since it uses less digits than its factorization.

324004113301142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 162002056650573.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 324004113301142 its reverse (241103311400423), we get a palindrome (565107424701565).

The spelling of 324004113301142 in words is "three hundred twenty-four trillion, four billion, one hundred thirteen million, three hundred one thousand, one hundred forty-two".

Divisors: 1 2 162002056650571 324004113301142