Base | Representation |
---|---|
bin | 100100110101011100001011… |
… | …0000101000011111010010110 |
3 | 1120111012111020202000010211202 |
4 | 1021222320112011003322112 |
5 | 314431440411001114032 |
6 | 3105033233530432502 |
7 | 125150344654142531 |
oct | 11152702605037226 |
9 | 1514174222003752 |
10 | 324004113301142 |
11 | 9426841120915a |
12 | 3040a201b92732 |
13 | 10ba35c2725781 |
14 | 5a01c503dba18 |
15 | 276d155855d62 |
hex | 126ae16143e96 |
324004113301142 has 4 divisors (see below), whose sum is σ = 486006169951716. Its totient is φ = 162002056650570.
The previous prime is 324004113301027. The next prime is 324004113301199. The reversal of 324004113301142 is 241103311400423.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81001028325284 + ... + 81001028325287.
It is an arithmetic number, because the mean of its divisors is an integer number (121501542487929).
Almost surely, 2324004113301142 is an apocalyptic number.
324004113301142 is a deficient number, since it is larger than the sum of its proper divisors (162002056650574).
324004113301142 is a wasteful number, since it uses less digits than its factorization.
324004113301142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 162002056650573.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 324004113301142 its reverse (241103311400423), we get a palindrome (565107424701565).
The spelling of 324004113301142 in words is "three hundred twenty-four trillion, four billion, one hundred thirteen million, three hundred one thousand, one hundred forty-two".
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