Base | Representation |
---|---|
bin | 1100000100011111… |
… | …0001101111000011 |
3 | 22100210201011020202 |
4 | 3001013301233003 |
5 | 23113422311121 |
6 | 1253301155415 |
7 | 143201616605 |
oct | 30107615703 |
9 | 8323634222 |
10 | 3240041411 |
11 | 1412a12082 |
12 | 7650bbb6b |
13 | 3c834b189 |
14 | 22a44d175 |
15 | 13e6ac40b |
hex | c11f1bc3 |
3240041411 has 2 divisors, whose sum is σ = 3240041412. Its totient is φ = 3240041410.
The previous prime is 3240041393. The next prime is 3240041423. The reversal of 3240041411 is 1141400423.
3240041411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (1141400423) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3240041411 - 230 = 2166299587 is a prime.
It is not a weakly prime, because it can be changed into another prime (3240041461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1620020705 + 1620020706.
It is an arithmetic number, because the mean of its divisors is an integer number (1620020706).
Almost surely, 23240041411 is an apocalyptic number.
3240041411 is a deficient number, since it is larger than the sum of its proper divisors (1).
3240041411 is an equidigital number, since it uses as much as digits as its factorization.
3240041411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
The square root of 3240041411 is about 56921.3616404246. The cubic root of 3240041411 is about 1479.7335487880.
Adding to 3240041411 its reverse (1141400423), we get a palindrome (4381441834).
The spelling of 3240041411 in words is "three billion, two hundred forty million, forty-one thousand, four hundred eleven".
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