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324045131 is a prime number
BaseRepresentation
bin10011010100001…
…000100101001011
3211120202012100112
4103110020211023
51130423421011
652053224535
711013223664
oct2324104513
9746665315
10324045131
11156a079a3
129063214b
13521994a7
143107236b
151d6ad58b
hex1350894b

324045131 has 2 divisors, whose sum is σ = 324045132. Its totient is φ = 324045130.

The previous prime is 324045121. The next prime is 324045157. The reversal of 324045131 is 131540423.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-324045131 is a prime.

It is a super-2 number, since 2×3240451312 = 210010493849614322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 324045097 and 324045106.

It is not a weakly prime, because it can be changed into another prime (324045121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162022565 + 162022566.

It is an arithmetic number, because the mean of its divisors is an integer number (162022566).

Almost surely, 2324045131 is an apocalyptic number.

324045131 is a deficient number, since it is larger than the sum of its proper divisors (1).

324045131 is an equidigital number, since it uses as much as digits as its factorization.

324045131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 324045131 is about 18001.2535952361. The cubic root of 324045131 is about 686.8604342357.

Adding to 324045131 its reverse (131540423), we get a palindrome (455585554).

The spelling of 324045131 in words is "three hundred twenty-four million, forty-five thousand, one hundred thirty-one".