Base | Representation |
---|---|
bin | 101111001010011100101… |
… | …001000001011000010001 |
3 | 102110211200012000122000220 |
4 | 233022130221001120101 |
5 | 411100114013343213 |
6 | 10520524332303253 |
7 | 453104553563160 |
oct | 57123451013021 |
9 | 12424605018026 |
10 | 3241033340433 |
11 | 103a572910979 |
12 | 444173611b29 |
13 | 1a6822013075 |
14 | b2c1c8d13d7 |
15 | 59490269e23 |
hex | 2f29ca41611 |
3241033340433 has 64 divisors (see below), whose sum is σ = 5128257318912. Its totient is φ = 1782609903360.
The previous prime is 3241033340417. The next prime is 3241033340443. The reversal of 3241033340433 is 3340433301423.
It is not a de Polignac number, because 3241033340433 - 24 = 3241033340417 is a prime.
It is a super-2 number, since 2×32410333404332 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3241033340394 and 3241033340403.
It is not an unprimeable number, because it can be changed into a prime (3241033340443) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 12134263 + ... + 12398483.
It is an arithmetic number, because the mean of its divisors is an integer number (80129020608).
Almost surely, 23241033340433 is an apocalyptic number.
It is an amenable number.
3241033340433 is a deficient number, since it is larger than the sum of its proper divisors (1887223978479).
3241033340433 is a wasteful number, since it uses less digits than its factorization.
3241033340433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 264494.
The product of its (nonzero) digits is 93312, while the sum is 33.
Adding to 3241033340433 its reverse (3340433301423), we get a palindrome (6581466641856).
The spelling of 3241033340433 in words is "three trillion, two hundred forty-one billion, thirty-three million, three hundred forty thousand, four hundred thirty-three".
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