Base | Representation |
---|---|
bin | 1100000100101111… |
… | …1111001100110001 |
3 | 22100212210020021111 |
4 | 3001023333030301 |
5 | 23114213121022 |
6 | 1253340553321 |
7 | 143214164506 |
oct | 30113771461 |
9 | 8325706244 |
10 | 3241145137 |
11 | 14135a634a |
12 | 765552841 |
13 | 3c8646679 |
14 | 22a6594ad |
15 | 13e829477 |
hex | c12ff331 |
3241145137 has 2 divisors, whose sum is σ = 3241145138. Its totient is φ = 3241145136.
The previous prime is 3241145123. The next prime is 3241145143. The reversal of 3241145137 is 7315411423.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3167888656 + 73256481 = 56284^2 + 8559^2 .
It is a cyclic number.
It is not a de Polignac number, because 3241145137 - 211 = 3241143089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3241145099 and 3241145108.
It is not a weakly prime, because it can be changed into another prime (3241145107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1620572568 + 1620572569.
It is an arithmetic number, because the mean of its divisors is an integer number (1620572569).
Almost surely, 23241145137 is an apocalyptic number.
It is an amenable number.
3241145137 is a deficient number, since it is larger than the sum of its proper divisors (1).
3241145137 is an equidigital number, since it uses as much as digits as its factorization.
3241145137 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10080, while the sum is 31.
The square root of 3241145137 is about 56931.0559975836. The cubic root of 3241145137 is about 1479.9015543539.
The spelling of 3241145137 in words is "three billion, two hundred forty-one million, one hundred forty-five thousand, one hundred thirty-seven".
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