Base | Representation |
---|---|
bin | 1110101111100011001011… |
… | …11111001001000101110011 |
3 | 11020210100000012100022220001 |
4 | 13113301211333021011303 |
5 | 13222132403243420311 |
6 | 152541333251530431 |
7 | 6554163620602216 |
oct | 727614577110563 |
9 | 136710005308801 |
10 | 32420124201331 |
11 | a36a32aa14589 |
12 | 37772a1bb9a17 |
13 | 1512287654899 |
14 | 8011dc9b577d |
15 | 3b34c62a14c1 |
hex | 1d7c65fc9173 |
32420124201331 has 2 divisors, whose sum is σ = 32420124201332. Its totient is φ = 32420124201330.
The previous prime is 32420124201293. The next prime is 32420124201341. The reversal of 32420124201331 is 13310242102423.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 32420124201331 - 217 = 32420124070259 is a prime.
It is a super-2 number, since 2×324201242013312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 32420124201331.
It is not a weakly prime, because it can be changed into another prime (32420124201341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16210062100665 + 16210062100666.
It is an arithmetic number, because the mean of its divisors is an integer number (16210062100666).
Almost surely, 232420124201331 is an apocalyptic number.
32420124201331 is a deficient number, since it is larger than the sum of its proper divisors (1).
32420124201331 is an equidigital number, since it uses as much as digits as its factorization.
32420124201331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 32420124201331 its reverse (13310242102423), we get a palindrome (45730366303754).
The spelling of 32420124201331 in words is "thirty-two trillion, four hundred twenty billion, one hundred twenty-four million, two hundred one thousand, three hundred thirty-one".
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