Base | Representation |
---|---|
bin | 11110001101001101… |
… | …111101111100100011 |
3 | 10002201101022221021212 |
4 | 132031031331330203 |
5 | 1012411102121011 |
6 | 22522221340335 |
7 | 2225513423312 |
oct | 361515757443 |
9 | 102641287255 |
10 | 32434020131 |
11 | 12834182417 |
12 | 63521076ab |
13 | 309b7327b6 |
14 | 17d9802279 |
15 | c9c67008b |
hex | 78d37df23 |
32434020131 has 2 divisors, whose sum is σ = 32434020132. Its totient is φ = 32434020130.
The previous prime is 32434020127. The next prime is 32434020137. The reversal of 32434020131 is 13102043423.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 32434020131 - 22 = 32434020127 is a prime.
It is a super-2 number, since 2×324340201312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 32434020097 and 32434020106.
It is not a weakly prime, because it can be changed into another prime (32434020137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16217010065 + 16217010066.
It is an arithmetic number, because the mean of its divisors is an integer number (16217010066).
Almost surely, 232434020131 is an apocalyptic number.
32434020131 is a deficient number, since it is larger than the sum of its proper divisors (1).
32434020131 is an equidigital number, since it uses as much as digits as its factorization.
32434020131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 32434020131 its reverse (13102043423), we get a palindrome (45536063554).
The spelling of 32434020131 in words is "thirty-two billion, four hundred thirty-four million, twenty thousand, one hundred thirty-one".
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