Base | Representation |
---|---|
bin | 11110001101110100… |
… | …000010101101011001 |
3 | 10002202002010000121212 |
4 | 132031310002231121 |
5 | 1012421131013423 |
6 | 22523215312505 |
7 | 2225664313346 |
oct | 361564025531 |
9 | 102662100555 |
10 | 32444001113 |
11 | 1283987a267 |
12 | 635551b735 |
13 | 30a08187c4 |
14 | 17dac7d7cd |
15 | c9d492578 |
hex | 78dd02b59 |
32444001113 has 2 divisors, whose sum is σ = 32444001114. Its totient is φ = 32444001112.
The previous prime is 32444001077. The next prime is 32444001119. The reversal of 32444001113 is 31110044423.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32030976784 + 413024329 = 178972^2 + 20323^2 .
It is a cyclic number.
It is not a de Polignac number, because 32444001113 - 218 = 32443738969 is a prime.
It is a super-2 number, since 2×324440011132 (a number of 22 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (32444001119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16222000556 + 16222000557.
It is an arithmetic number, because the mean of its divisors is an integer number (16222000557).
Almost surely, 232444001113 is an apocalyptic number.
It is an amenable number.
32444001113 is a deficient number, since it is larger than the sum of its proper divisors (1).
32444001113 is an equidigital number, since it uses as much as digits as its factorization.
32444001113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 32444001113 its reverse (31110044423), we get a palindrome (63554045536).
The spelling of 32444001113 in words is "thirty-two billion, four hundred forty-four million, one thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •