Base | Representation |
---|---|
bin | 1110110000010000010011… |
… | …00110111000100100110101 |
3 | 11020212122112010102210122120 |
4 | 13120020021212320210311 |
5 | 13223032004100022013 |
6 | 153000420445150153 |
7 | 6556012043651430 |
oct | 730101146704465 |
9 | 136778463383576 |
10 | 32444344142133 |
11 | a37962949a590 |
12 | 377bb2125b359 |
13 | 151464739a6c1 |
14 | 802459504817 |
15 | 3b3e4273a123 |
hex | 1d82099b8935 |
32444344142133 has 32 divisors (see below), whose sum is σ = 53933802381312. Its totient is φ = 16854096254400.
The previous prime is 32444344142131. The next prime is 32444344142141. The reversal of 32444344142133 is 33124144344423.
It is not a de Polignac number, because 32444344142133 - 21 = 32444344142131 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (32444344142131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 45676860 + ... + 46381722.
It is an arithmetic number, because the mean of its divisors is an integer number (1685431324416).
Almost surely, 232444344142133 is an apocalyptic number.
32444344142133 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
32444344142133 is a deficient number, since it is larger than the sum of its proper divisors (21489458239179).
32444344142133 is a wasteful number, since it uses less digits than its factorization.
32444344142133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 904145.
The product of its digits is 1327104, while the sum is 42.
Adding to 32444344142133 its reverse (33124144344423), we get a palindrome (65568488486556).
The spelling of 32444344142133 in words is "thirty-two trillion, four hundred forty-four billion, three hundred forty-four million, one hundred forty-two thousand, one hundred thirty-three".
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