Base | Representation |
---|---|
bin | 101111010001111101111… |
… | …111011110101011010001 |
3 | 102111121111222221010022022 |
4 | 233101331333132223101 |
5 | 411213133410142442 |
6 | 10524341535221225 |
7 | 453511644254645 |
oct | 57217577365321 |
9 | 12447458833268 |
10 | 3249109068497 |
11 | 1042a374019a6 |
12 | 445848077815 |
13 | 1a750b14bc96 |
14 | b338726cc25 |
15 | 597b42233d2 |
hex | 2f47dfdead1 |
3249109068497 has 2 divisors, whose sum is σ = 3249109068498. Its totient is φ = 3249109068496.
The previous prime is 3249109068487. The next prime is 3249109068577. The reversal of 3249109068497 is 7948609019423.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3248847631936 + 261436561 = 1802456^2 + 16169^2 .
It is a cyclic number.
It is not a de Polignac number, because 3249109068497 - 28 = 3249109068241 is a prime.
It is a super-3 number, since 3×32491090684973 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (3249109068487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1624554534248 + 1624554534249.
It is an arithmetic number, because the mean of its divisors is an integer number (1624554534249).
Almost surely, 23249109068497 is an apocalyptic number.
It is an amenable number.
3249109068497 is a deficient number, since it is larger than the sum of its proper divisors (1).
3249109068497 is an equidigital number, since it uses as much as digits as its factorization.
3249109068497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23514624, while the sum is 62.
The spelling of 3249109068497 in words is "three trillion, two hundred forty-nine billion, one hundred nine million, sixty-eight thousand, four hundred ninety-seven".
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