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3250053123049 is a prime number
BaseRepresentation
bin101111010010110110010…
…000110000101111101001
3102111200221210100001200201
4233102312100300233221
5411222102044414144
610525015341432201
7453544226506405
oct57226620605751
912450853301621
103250053123049
111043381294077
12445a7026b661
131a762b8cb845
14b34367b6105
155981c0531d4
hex2f4b6430be9

3250053123049 has 2 divisors, whose sum is σ = 3250053123050. Its totient is φ = 3250053123048.

The previous prime is 3250053123019. The next prime is 3250053123059. The reversal of 3250053123049 is 9403213500523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1882397720025 + 1367655403024 = 1372005^2 + 1169468^2 .

It is a cyclic number.

It is not a de Polignac number, because 3250053123049 - 213 = 3250053114857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3250053122999 and 3250053123017.

It is not a weakly prime, because it can be changed into another prime (3250053123019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1625026561524 + 1625026561525.

It is an arithmetic number, because the mean of its divisors is an integer number (1625026561525).

Almost surely, 23250053123049 is an apocalyptic number.

It is an amenable number.

3250053123049 is a deficient number, since it is larger than the sum of its proper divisors (1).

3250053123049 is an equidigital number, since it uses as much as digits as its factorization.

3250053123049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 37.

The spelling of 3250053123049 in words is "three trillion, two hundred fifty billion, fifty-three million, one hundred twenty-three thousand, forty-nine".