325020401341 has 4 divisors (see below), whose sum is σ = 326670251292. Its totient is φ = 323370551392.

The previous prime is 325020401333. The next prime is 325020401357. The reversal of 325020401341 is 143104020523.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 311458867225 + 13561534116 = 558085^2 + 116454^2 .

It is a cyclic number.

It is not a de Polignac number, because 325020401341 - 2³ = 325020401333 is a prime.

It is a super-2 number, since 2×325020401341² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (325020401311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 824924680 + ... + 824925073.

It is an arithmetic number, because the mean of its divisors is an integer number (81667562823).

Almost surely, 2^325020401341 is an apocalyptic number.

It is an amenable number.

325020401341 is a deficient number, since it is larger than the sum of its proper divisors (1649849951).

325020401341 is a wasteful number, since it uses less digits than its factorization.

325020401341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1649849950.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 325020401341 its reverse (143104020523), we get a palindrome (468124421864).

The spelling of 325020401341 in words is "three hundred twenty-five billion, twenty million, four hundred one thousand, three hundred forty-one".