Base | Representation |
---|---|
bin | 101111010010111111110… |
… | …110100000010010010111 |
3 | 102111201101000002001220210 |
4 | 233102333312200102113 |
5 | 411222414241341210 |
6 | 10525043330100503 |
7 | 453551222160513 |
oct | 57227766402227 |
9 | 12451330061823 |
10 | 3250214012055 |
11 | 104345409339a |
12 | 445ab611a733 |
13 | 1a7656040b3a |
14 | b344dcd7143 |
15 | 5982b233e20 |
hex | 2f4bfda0497 |
3250214012055 has 8 divisors (see below), whose sum is σ = 5200342419312. Its totient is φ = 1733447473088.
The previous prime is 3250214011997. The next prime is 3250214012057. The reversal of 3250214012055 is 5502104120523.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3250214012055 - 28 = 3250214011799 is a prime.
It is a super-2 number, since 2×32502140120552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3250214012057) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108340467054 + ... + 108340467083.
It is an arithmetic number, because the mean of its divisors is an integer number (650042802414).
Almost surely, 23250214012055 is an apocalyptic number.
3250214012055 is a deficient number, since it is larger than the sum of its proper divisors (1950128407257).
3250214012055 is a wasteful number, since it uses less digits than its factorization.
3250214012055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 216680934145.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 3250214012055 its reverse (5502104120523), we get a palindrome (8752318132578).
The spelling of 3250214012055 in words is "three trillion, two hundred fifty billion, two hundred fourteen million, twelve thousand, fifty-five".
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