Base | Representation |
---|---|
bin | 101111010011000111001… |
… | …000111110110111111101 |
3 | 102111201200112011202120021 |
4 | 233103013020332313331 |
5 | 411223142042441240 |
6 | 10525103415052141 |
7 | 453554235445000 |
oct | 57230710766775 |
9 | 12451615152507 |
10 | 3250336296445 |
11 | 1043507115477 |
12 | 445b2b071051 |
13 | 1a7675487774 |
14 | b3462249537 |
15 | 59836d3b54a |
hex | 2f4c723edfd |
3250336296445 has 32 divisors (see below), whose sum is σ = 4548786739200. Its totient is φ = 2228698563840.
The previous prime is 3250336296439. The next prime is 3250336296491. The reversal of 3250336296445 is 5446926330523.
It is not a de Polignac number, because 3250336296445 - 29 = 3250336295933 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3250336296392 and 3250336296401.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 64566885 + ... + 64617205.
It is an arithmetic number, because the mean of its divisors is an integer number (142149585600).
Almost surely, 23250336296445 is an apocalyptic number.
3250336296445 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
3250336296445 is a deficient number, since it is larger than the sum of its proper divisors (1298450442755).
3250336296445 is an equidigital number, since it uses as much as digits as its factorization.
3250336296445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 88010 (or 87996 counting only the distinct ones).
The product of its (nonzero) digits is 13996800, while the sum is 52.
The spelling of 3250336296445 in words is "three trillion, two hundred fifty billion, three hundred thirty-six million, two hundred ninety-six thousand, four hundred forty-five".
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