325040130011253 has 8 divisors (see below), whose sum is σ = 434062950532416. Its totient is φ = 216355364748800.

The previous prime is 325040130011251. The next prime is 325040130011297. The reversal of 325040130011253 is 352110031040523.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 325040130011253 - 2¹ = 325040130011251 is a prime.

It is a super-3 number, since 3×325040130011253³ (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 325040130011253.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (325040130011251) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 84513812433 + ... + 84513816278.

It is an arithmetic number, because the mean of its divisors is an integer number (54257868816552).

Almost surely, 2^{325040130011253} is an apocalyptic number.

It is an amenable number.

325040130011253 is a deficient number, since it is larger than the sum of its proper divisors (109022820521163).

325040130011253 is a wasteful number, since it uses less digits than its factorization.

325040130011253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 169027629355.

The product of its (nonzero) digits is 10800, while the sum is 30.

Adding to 325040130011253 its reverse (352110031040523), we get a palindrome (677150161051776).

The spelling of 325040130011253 in words is "three hundred twenty-five trillion, forty billion, one hundred thirty million, eleven thousand, two hundred fifty-three".