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325115055455041 is a prime number
BaseRepresentation
bin100100111101100001011111…
…1011001000011101101000001
31120122010200210012122220212201
41021323002333121003231001
5320103141113144030131
63111243443344353201
7125323534103506435
oct11173027731035501
91518120705586781
10325115055455041
1194656580088345
1230569586315801
1310c542ab453907
145a3d91cbd89c5
15278bec6c6b761
hex127b0bf643b41

325115055455041 has 2 divisors, whose sum is σ = 325115055455042. Its totient is φ = 325115055455040.

The previous prime is 325115055455027. The next prime is 325115055455161. The reversal of 325115055455041 is 140554550511523.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 305553196806400 + 19561858648641 = 17480080^2 + 4422879^2 .

It is a cyclic number.

It is not a de Polignac number, because 325115055455041 - 213 = 325115055446849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 325115055454982 and 325115055455000.

It is not a weakly prime, because it can be changed into another prime (325115055455341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162557527727520 + 162557527727521.

It is an arithmetic number, because the mean of its divisors is an integer number (162557527727521).

Almost surely, 2325115055455041 is an apocalyptic number.

It is an amenable number.

325115055455041 is a deficient number, since it is larger than the sum of its proper divisors (1).

325115055455041 is an equidigital number, since it uses as much as digits as its factorization.

325115055455041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1500000, while the sum is 46.

The spelling of 325115055455041 in words is "three hundred twenty-five trillion, one hundred fifteen billion, fifty-five million, four hundred fifty-five thousand, forty-one".