Base | Representation |
---|---|
bin | 1110110010010000011001… |
… | …00100011010000011111001 |
3 | 11021010020000202202001020110 |
4 | 13121020030210122003321 |
5 | 13230143324001114431 |
6 | 153052152411014533 |
7 | 6563665154112606 |
oct | 731101444320371 |
9 | 137106022661213 |
10 | 32513113301241 |
11 | a3a5808930681 |
12 | 3791313a3a449 |
13 | 151ac86812c21 |
14 | 80590087d6ad |
15 | 3b5b19c6c346 |
hex | 1d920c91a0f9 |
32513113301241 has 16 divisors (see below), whose sum is σ = 45634317307200. Its totient is φ = 20533752960768.
The previous prime is 32513113301237. The next prime is 32513113301257. The reversal of 32513113301241 is 14210331131523.
It is not a de Polignac number, because 32513113301241 - 22 = 32513113301237 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32513113301199 and 32513113301208.
It is not an unprimeable number, because it can be changed into a prime (32513113301281) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10335996 + ... + 13109501.
It is an arithmetic number, because the mean of its divisors is an integer number (2852144831700).
Almost surely, 232513113301241 is an apocalyptic number.
It is an amenable number.
32513113301241 is a deficient number, since it is larger than the sum of its proper divisors (13121204005959).
32513113301241 is a wasteful number, since it uses less digits than its factorization.
32513113301241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23469848.
The product of its (nonzero) digits is 6480, while the sum is 30.
Adding to 32513113301241 its reverse (14210331131523), we get a palindrome (46723444432764).
The spelling of 32513113301241 in words is "thirty-two trillion, five hundred thirteen billion, one hundred thirteen million, three hundred one thousand, two hundred forty-one".
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