Base | Representation |
---|---|
bin | 1110110010100110100101… |
… | …10111000000100001110001 |
3 | 11021011100210021010002210122 |
4 | 13121103102313000201301 |
5 | 13230342230140011003 |
6 | 153101443103140025 |
7 | 6564566364306023 |
oct | 731232267004161 |
9 | 137140707102718 |
10 | 32525030000753 |
11 | a3aa873567374 |
12 | 379369a8a4615 |
13 | 151c135630004 |
14 | 8063113b6013 |
15 | 3b60b6036238 |
hex | 1d94d2dc0871 |
32525030000753 has 2 divisors, whose sum is σ = 32525030000754. Its totient is φ = 32525030000752.
The previous prime is 32525030000719. The next prime is 32525030000759. The reversal of 32525030000753 is 35700003052523.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32426840524849 + 98189475904 = 5694457^2 + 313352^2 .
It is a cyclic number.
It is not a de Polignac number, because 32525030000753 - 228 = 32524761565297 is a prime.
It is a super-3 number, since 3×325250300007533 (a number of 42 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (32525030000759) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16262515000376 + 16262515000377.
It is an arithmetic number, because the mean of its divisors is an integer number (16262515000377).
Almost surely, 232525030000753 is an apocalyptic number.
It is an amenable number.
32525030000753 is a deficient number, since it is larger than the sum of its proper divisors (1).
32525030000753 is an equidigital number, since it uses as much as digits as its factorization.
32525030000753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 94500, while the sum is 35.
The spelling of 32525030000753 in words is "thirty-two trillion, five hundred twenty-five billion, thirty million, seven hundred fifty-three", and thus it is an aban number.
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