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3253105201513 is a prime number
BaseRepresentation
bin101111010101101100001…
…011100001000101101001
3102111222211111100201020211
4233111230023201011221
5411244324412422023
610530242250221121
7454012656654346
oct57255413410551
912458744321224
103253105201513
1110446a8094872
124465824247a1
131a79c701852b
14b3645c977cd
1559949e82a0d
hex2f56c2e1169

3253105201513 has 2 divisors, whose sum is σ = 3253105201514. Its totient is φ = 3253105201512.

The previous prime is 3253105201469. The next prime is 3253105201519. The reversal of 3253105201513 is 3151025013523.

3253105201513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3022636076329 + 230469125184 = 1738573^2 + 480072^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3253105201513 is a prime.

It is a super-2 number, since 2×32531052015132 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3253105201519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1626552600756 + 1626552600757.

It is an arithmetic number, because the mean of its divisors is an integer number (1626552600757).

Almost surely, 23253105201513 is an apocalyptic number.

It is an amenable number.

3253105201513 is a deficient number, since it is larger than the sum of its proper divisors (1).

3253105201513 is an equidigital number, since it uses as much as digits as its factorization.

3253105201513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 31.

The spelling of 3253105201513 in words is "three trillion, two hundred fifty-three billion, one hundred five million, two hundred one thousand, five hundred thirteen".