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325316410556161 is a prime number
BaseRepresentation
bin100100111110111111010000…
…1000101110011111100000001
31120122211221111222210212122111
41021331332201011303330001
5320114441002100244121
63111520143523135321
7125344222630565533
oct11175764105637401
91518757458725574
10325316410556161
1194723a07861022
12305a05bb814541
1310c6a28a430c6b
145a49580c61853
15279235e1672e1
hex127dfa1173f01

325316410556161 has 2 divisors, whose sum is σ = 325316410556162. Its totient is φ = 325316410556160.

The previous prime is 325316410556147. The next prime is 325316410556191. The reversal of 325316410556161 is 161655014613523.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 293049239179761 + 32267171376400 = 17118681^2 + 5680420^2 .

It is an emirp because it is prime and its reverse (161655014613523) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 325316410556161 - 227 = 325316276338433 is a prime.

It is a super-2 number, since 2×3253164105561612 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (325316410556191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162658205278080 + 162658205278081.

It is an arithmetic number, because the mean of its divisors is an integer number (162658205278081).

Almost surely, 2325316410556161 is an apocalyptic number.

It is an amenable number.

325316410556161 is a deficient number, since it is larger than the sum of its proper divisors (1).

325316410556161 is an equidigital number, since it uses as much as digits as its factorization.

325316410556161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944000, while the sum is 49.

The spelling of 325316410556161 in words is "three hundred twenty-five trillion, three hundred sixteen billion, four hundred ten million, five hundred fifty-six thousand, one hundred sixty-one".