Base | Representation |
---|---|
bin | 1001011110000000110… |
… | …00010001001011100001 |
3 | 1011002210012200021210101 |
4 | 10233000120101023201 |
5 | 20312304113300442 |
6 | 405244102302401 |
7 | 32335323341113 |
oct | 4570030211341 |
9 | 1132705607711 |
10 | 325350134497 |
11 | 115a8673a583 |
12 | 5307b127a01 |
13 | 248aca675ab |
14 | 11a65bcd3b3 |
15 | 86e2e94cb7 |
hex | 4bc06112e1 |
325350134497 has 2 divisors, whose sum is σ = 325350134498. Its totient is φ = 325350134496.
The previous prime is 325350134479. The next prime is 325350134533. The reversal of 325350134497 is 794431053523.
Together with previous prime (325350134479) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 324579738961 + 770395536 = 569719^2 + 27756^2 .
It is an emirp because it is prime and its reverse (794431053523) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 325350134497 - 211 = 325350132449 is a prime.
It is not a weakly prime, because it can be changed into another prime (325350134477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162675067248 + 162675067249.
It is an arithmetic number, because the mean of its divisors is an integer number (162675067249).
Almost surely, 2325350134497 is an apocalyptic number.
It is an amenable number.
325350134497 is a deficient number, since it is larger than the sum of its proper divisors (1).
325350134497 is an equidigital number, since it uses as much as digits as its factorization.
325350134497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1360800, while the sum is 46.
The spelling of 325350134497 in words is "three hundred twenty-five billion, three hundred fifty million, one hundred thirty-four thousand, four hundred ninety-seven".
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