325365301141 has 4 divisors (see below), whose sum is σ = 325370475232. Its totient is φ = 325360127052.

The previous prime is 325365301123. The next prime is 325365301181. The reversal of 325365301141 is 141103563523.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 325365301141 - 2⁵ = 325365301109 is a prime.

It is a super-3 number, since 3×325365301141³ (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 325365301097 and 325365301106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (325365301181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2491545 + ... + 2618878.

It is an arithmetic number, because the mean of its divisors is an integer number (81342618808).

Almost surely, 2^325365301141 is an apocalyptic number.

It is an amenable number.

325365301141 is a deficient number, since it is larger than the sum of its proper divisors (5174091).

325365301141 is an equidigital number, since it uses as much as digits as its factorization.

325365301141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5174090.

The product of its (nonzero) digits is 32400, while the sum is 34.

Adding to 325365301141 its reverse (141103563523), we get a palindrome (466468864664).

The spelling of 325365301141 in words is "three hundred twenty-five billion, three hundred sixty-five million, three hundred one thousand, one hundred forty-one".