Search a number
-
+
325413424314553 is a prime number
BaseRepresentation
bin100100111111101100011011…
…1100011111011100010111001
31120200012012221001022102112011
41021333120313203323202321
5320123033143111031203
63112032510252445521
7125354226004123351
oct11177306743734271
91520165831272464
10325413424314553
1194761070573653
12305b73754798a1
1310c7647b365623
145a5014545bb61
152794b3b12976d
hex127f6378fb8b9

325413424314553 has 2 divisors, whose sum is σ = 325413424314554. Its totient is φ = 325413424314552.

The previous prime is 325413424314491. The next prime is 325413424314599. The reversal of 325413424314553 is 355413424314523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 182918781414009 + 142494642900544 = 13524747^2 + 11937112^2 .

It is a cyclic number.

It is not a de Polignac number, because 325413424314553 - 213 = 325413424306361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 325413424314497 and 325413424314506.

It is not a weakly prime, because it can be changed into another prime (325413424314053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162706712157276 + 162706712157277.

It is an arithmetic number, because the mean of its divisors is an integer number (162706712157277).

Almost surely, 2325413424314553 is an apocalyptic number.

It is an amenable number.

325413424314553 is a deficient number, since it is larger than the sum of its proper divisors (1).

325413424314553 is an equidigital number, since it uses as much as digits as its factorization.

325413424314553 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10368000, while the sum is 49.

The spelling of 325413424314553 in words is "three hundred twenty-five trillion, four hundred thirteen billion, four hundred twenty-four million, three hundred fourteen thousand, five hundred fifty-three".