325440121 has 2 divisors, whose sum is σ = 325440122. Its totient is φ = 325440120.

The previous prime is 325440107. The next prime is 325440127. The reversal of 325440121 is 121044523.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 235929600 + 89510521 = 15360^2 + 9461^2 .

It is a cyclic number.

It is not a de Polignac number, because 325440121 - 2²⁵ = 291885689 is a prime.

It is a super-3 number, since 3×325440121³ (a number of 27 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 325440092 and 325440101.

It is not a weakly prime, because it can be changed into another prime (325440127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162720060 + 162720061.

It is an arithmetic number, because the mean of its divisors is an integer number (162720061).

Almost surely, 2^325440121 is an apocalyptic number.

It is an amenable number.

325440121 is a deficient number, since it is larger than the sum of its proper divisors (1).

325440121 is an equidigital number, since it uses as much as digits as its factorization.

325440121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 22.

The square root of 325440121 is about 18039.9590077140. The cubic root of 325440121 is about 687.8446508195.

Adding to 325440121 its reverse (121044523), we get a palindrome (446484644).

The spelling of 325440121 in words is "three hundred twenty-five million, four hundred forty thousand, one hundred twenty-one".