Base | Representation |
---|---|
bin | 100101000000100100101011… |
… | …1100111111100010010111011 |
3 | 1120200121202201121012011212211 |
4 | 1022001021113213330102323 |
5 | 320132023041124241103 |
6 | 3112204205015515551 |
7 | 125366033321545033 |
oct | 11201112747742273 |
9 | 1520552647164784 |
10 | 325534221321403 |
11 | 947a8319304816 |
12 | 30616868088bb7 |
13 | 10c8498c6c5383 |
14 | 5a55d245908c3 |
15 | 2797d5b06536d |
hex | 12812579fc4bb |
325534221321403 has 2 divisors, whose sum is σ = 325534221321404. Its totient is φ = 325534221321402.
The previous prime is 325534221321367. The next prime is 325534221321467. The reversal of 325534221321403 is 304123122435523.
It is a weak prime.
It is an emirp because it is prime and its reverse (304123122435523) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 325534221321403 - 221 = 325534219224251 is a prime.
It is not a weakly prime, because it can be changed into another prime (325534221321703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162767110660701 + 162767110660702.
It is an arithmetic number, because the mean of its divisors is an integer number (162767110660702).
Almost surely, 2325534221321403 is an apocalyptic number.
325534221321403 is a deficient number, since it is larger than the sum of its proper divisors (1).
325534221321403 is an equidigital number, since it uses as much as digits as its factorization.
325534221321403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 325534221321403 its reverse (304123122435523), we get a palindrome (629657343756926).
The spelling of 325534221321403 in words is "three hundred twenty-five trillion, five hundred thirty-four billion, two hundred twenty-one million, three hundred twenty-one thousand, four hundred three".
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