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325534221321403 is a prime number
BaseRepresentation
bin100101000000100100101011…
…1100111111100010010111011
31120200121202201121012011212211
41022001021113213330102323
5320132023041124241103
63112204205015515551
7125366033321545033
oct11201112747742273
91520552647164784
10325534221321403
11947a8319304816
1230616868088bb7
1310c8498c6c5383
145a55d245908c3
152797d5b06536d
hex12812579fc4bb

325534221321403 has 2 divisors, whose sum is σ = 325534221321404. Its totient is φ = 325534221321402.

The previous prime is 325534221321367. The next prime is 325534221321467. The reversal of 325534221321403 is 304123122435523.

It is a weak prime.

It is an emirp because it is prime and its reverse (304123122435523) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 325534221321403 - 221 = 325534219224251 is a prime.

It is not a weakly prime, because it can be changed into another prime (325534221321703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162767110660701 + 162767110660702.

It is an arithmetic number, because the mean of its divisors is an integer number (162767110660702).

Almost surely, 2325534221321403 is an apocalyptic number.

325534221321403 is a deficient number, since it is larger than the sum of its proper divisors (1).

325534221321403 is an equidigital number, since it uses as much as digits as its factorization.

325534221321403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 325534221321403 its reverse (304123122435523), we get a palindrome (629657343756926).

The spelling of 325534221321403 in words is "three hundred twenty-five trillion, five hundred thirty-four billion, two hundred twenty-one million, three hundred twenty-one thousand, four hundred three".