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3255441281 is a prime number
BaseRepresentation
bin1100001000001010…
…0001011110000001
322101212200112220022
43002002201132001
523131343110111
61255011223225
7143446536311
oct30202413601
98355615808
103255441281
111420680244
1276a2a7b15
133cb5b0821
1422c4db441
15140c002db
hexc20a1781

3255441281 has 2 divisors, whose sum is σ = 3255441282. Its totient is φ = 3255441280.

The previous prime is 3255441271. The next prime is 3255441311. The reversal of 3255441281 is 1821445523.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3205258225 + 50183056 = 56615^2 + 7084^2 .

It is an emirp because it is prime and its reverse (1821445523) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3255441281 is a prime.

It is a super-2 number, since 2×32554412812 = 21195795868077841922, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3255441271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1627720640 + 1627720641.

It is an arithmetic number, because the mean of its divisors is an integer number (1627720641).

Almost surely, 23255441281 is an apocalyptic number.

It is an amenable number.

3255441281 is a deficient number, since it is larger than the sum of its proper divisors (1).

3255441281 is an equidigital number, since it uses as much as digits as its factorization.

3255441281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 38400, while the sum is 35.

The square root of 3255441281 is about 57056.4744880018. The cubic root of 3255441281 is about 1482.0742283474.

The spelling of 3255441281 in words is "three billion, two hundred fifty-five million, four hundred forty-one thousand, two hundred eighty-one".