Base | Representation |
---|---|
bin | 100101000001001010011100… |
… | …1000101111010111011111011 |
3 | 1120200220112001001100220100201 |
4 | 1022002110321011322323323 |
5 | 320134340130221340313 |
6 | 3112305335425543031 |
7 | 125404634004442015 |
oct | 11202247105727373 |
9 | 1520815031326321 |
10 | 325615313465083 |
11 | 9482975174a584 |
12 | 3062a5197a4a77 |
13 | 10c8c513b89c45 |
14 | 5a59c183c11b5 |
15 | 279a0053670dd |
hex | 128253917aefb |
325615313465083 has 2 divisors, whose sum is σ = 325615313465084. Its totient is φ = 325615313465082.
The previous prime is 325615313465053. The next prime is 325615313465161. The reversal of 325615313465083 is 380564313516523.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 325615313465083 - 25 = 325615313465051 is a prime.
It is not a weakly prime, because it can be changed into another prime (325615313465053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 162807656732541 + 162807656732542.
It is an arithmetic number, because the mean of its divisors is an integer number (162807656732542).
Almost surely, 2325615313465083 is an apocalyptic number.
325615313465083 is a deficient number, since it is larger than the sum of its proper divisors (1).
325615313465083 is an equidigital number, since it uses as much as digits as its factorization.
325615313465083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328000, while the sum is 55.
The spelling of 325615313465083 in words is "three hundred twenty-five trillion, six hundred fifteen billion, three hundred thirteen million, four hundred sixty-five thousand, eighty-three".
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