Base | Representation |
---|---|
bin | 100101000111000010110010… |
… | …1100010111010011000010011 |
3 | 1120210202210010212120222020211 |
4 | 1022032011211202322120103 |
5 | 320241110323324123011 |
6 | 3114124520341144551 |
7 | 125520214645220266 |
oct | 11216054542723023 |
9 | 1523683125528224 |
10 | 326423513114131 |
11 | 95010486344a34 |
12 | 3073b0920bb157 |
13 | 1101a7b3840054 |
14 | 5a86da7740cdd |
15 | 27b105843eb21 |
hex | 128e1658ba613 |
326423513114131 has 2 divisors, whose sum is σ = 326423513114132. Its totient is φ = 326423513114130.
The previous prime is 326423513114093. The next prime is 326423513114143. The reversal of 326423513114131 is 131411315324623.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 326423513114131 - 223 = 326423504725523 is a prime.
It is a super-2 number, since 2×3264235131141312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (326423513114431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 163211756557065 + 163211756557066.
It is an arithmetic number, because the mean of its divisors is an integer number (163211756557066).
Almost surely, 2326423513114131 is an apocalyptic number.
326423513114131 is a deficient number, since it is larger than the sum of its proper divisors (1).
326423513114131 is an equidigital number, since it uses as much as digits as its factorization.
326423513114131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 40.
Adding to 326423513114131 its reverse (131411315324623), we get a palindrome (457834828438754).
The spelling of 326423513114131 in words is "three hundred twenty-six trillion, four hundred twenty-three billion, five hundred thirteen million, one hundred fourteen thousand, one hundred thirty-one".
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