Base | Representation |
---|---|
bin | 1110110110000010110100… |
… | …01100010111010000000011 |
3 | 11021120122222020110002121121 |
4 | 13123001122030113100003 |
5 | 13234311401221440003 |
6 | 153232035253533111 |
7 | 6606253346204053 |
oct | 733013214272003 |
9 | 137518866402547 |
10 | 32643264640003 |
11 | a445a26976866 |
12 | 37b2597344197 |
13 | 152a328b64b04 |
14 | 80bd2a0a1563 |
15 | 3b91d6026cbd |
hex | 1db05a317403 |
32643264640003 has 2 divisors, whose sum is σ = 32643264640004. Its totient is φ = 32643264640002.
The previous prime is 32643264639941. The next prime is 32643264640043. The reversal of 32643264640003 is 30004646234623.
It is a strong prime.
It is an emirp because it is prime and its reverse (30004646234623) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 32643264640003 - 217 = 32643264508931 is a prime.
It is not a weakly prime, because it can be changed into another prime (32643264640043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16321632320001 + 16321632320002.
It is an arithmetic number, because the mean of its divisors is an integer number (16321632320002).
Almost surely, 232643264640003 is an apocalyptic number.
32643264640003 is a deficient number, since it is larger than the sum of its proper divisors (1).
32643264640003 is an equidigital number, since it uses as much as digits as its factorization.
32643264640003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1492992, while the sum is 43.
The spelling of 32643264640003 in words is "thirty-two trillion, six hundred forty-three billion, two hundred sixty-four million, six hundred forty thousand, three".
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