Base | Representation |
---|---|
bin | 101111101010000000000… |
… | …101100010111101101001 |
3 | 102121002010101111100001112 |
4 | 233222000011202331221 |
5 | 412124010442022004 |
6 | 10544250313000105 |
7 | 455414264563226 |
oct | 57520005427551 |
9 | 12532111440045 |
10 | 3274914017129 |
11 | 1052979649827 |
12 | 44a84a0b3035 |
13 | 1a9a9137b961 |
14 | b47144ac94d |
15 | 5a2c48e8e6e |
hex | 2fa80162f69 |
3274914017129 has 2 divisors, whose sum is σ = 3274914017130. Its totient is φ = 3274914017128.
The previous prime is 3274914017077. The next prime is 3274914017173. The reversal of 3274914017129 is 9217104194723.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3180419257129 + 94494760000 = 1783373^2 + 307400^2 .
It is an emirp because it is prime and its reverse (9217104194723) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3274914017129 - 216 = 3274913951593 is a prime.
It is not a weakly prime, because it can be changed into another prime (3274914011129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1637457008564 + 1637457008565.
It is an arithmetic number, because the mean of its divisors is an integer number (1637457008565).
Almost surely, 23274914017129 is an apocalyptic number.
It is an amenable number.
3274914017129 is a deficient number, since it is larger than the sum of its proper divisors (1).
3274914017129 is an equidigital number, since it uses as much as digits as its factorization.
3274914017129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 762048, while the sum is 50.
The spelling of 3274914017129 in words is "three trillion, two hundred seventy-four billion, nine hundred fourteen million, seventeen thousand, one hundred twenty-nine".
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