3280995743 has 4 divisors (see below), whose sum is σ = 3281121720. Its totient is φ = 3280869768.

The previous prime is 3280995737. The next prime is 3280995779. The reversal of 3280995743 is 3475990823.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3475990823 = 1109 ⋅3134347.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3280995743 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3280995691 and 3280995700.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3280995703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7808 + ... + 81381.

It is an arithmetic number, because the mean of its divisors is an integer number (820280430).

Almost surely, 2^3280995743 is an apocalyptic number.

3280995743 is a deficient number, since it is larger than the sum of its proper divisors (125977).

3280995743 is an equidigital number, since it uses as much as digits as its factorization.

3280995743 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125976.

The product of its (nonzero) digits is 1632960, while the sum is 50.

The square root of 3280995743 is about 57279.9768069087. The cubic root of 3280995743 is about 1485.9421053895.

The spelling of 3280995743 in words is "three billion, two hundred eighty million, nine hundred ninety-five thousand, seven hundred forty-three".