Base | Representation |
---|---|
bin | 101111110101000000000… |
… | …011111001001100111001 |
3 | 102122012121111110102110211 |
4 | 233311000003321030321 |
5 | 412322203013301433 |
6 | 10553522301511121 |
7 | 456313050240235 |
oct | 57650003711471 |
9 | 12565544412424 |
10 | 3286724743993 |
11 | 105798a484719 |
12 | 450ba55724a1 |
13 | 1aac24243832 |
14 | b5114cdb5c5 |
15 | 5a76672d8cd |
hex | 2fd400f9339 |
3286724743993 has 2 divisors, whose sum is σ = 3286724743994. Its totient is φ = 3286724743992.
The previous prime is 3286724743969. The next prime is 3286724744003. The reversal of 3286724743993 is 3993474276823.
3286724743993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3264515399209 + 22209344784 = 1806797^2 + 149028^2 .
It is a cyclic number.
It is not a de Polignac number, because 3286724743993 - 29 = 3286724743481 is a prime.
It is not a weakly prime, because it can be changed into another prime (3286724743933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1643362371996 + 1643362371997.
It is an arithmetic number, because the mean of its divisors is an integer number (1643362371997).
Almost surely, 23286724743993 is an apocalyptic number.
It is an amenable number.
3286724743993 is a deficient number, since it is larger than the sum of its proper divisors (1).
3286724743993 is an equidigital number, since it uses as much as digits as its factorization.
3286724743993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 329204736, while the sum is 67.
The spelling of 3286724743993 in words is "three trillion, two hundred eighty-six billion, seven hundred twenty-four million, seven hundred forty-three thousand, nine hundred ninety-three".
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