Base | Representation |
---|---|
bin | 110000000000011000011… |
… | …001001000010011111001 |
3 | 102200101011002101020211101 |
4 | 300000120121020103321 |
5 | 413022214143433103 |
6 | 11003303005331401 |
7 | 460224624246256 |
oct | 60003031102371 |
9 | 12611132336741 |
10 | 3298944124153 |
11 | 106208aa55907 |
12 | 453435866b61 |
13 | 1ac1209898b2 |
14 | b5953b0442d |
15 | 5ac2e385a1d |
hex | 300186484f9 |
3298944124153 has 2 divisors, whose sum is σ = 3298944124154. Its totient is φ = 3298944124152.
The previous prime is 3298944124097. The next prime is 3298944124171. The reversal of 3298944124153 is 3514214498923.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2829214828729 + 469729295424 = 1682027^2 + 685368^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3298944124153 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3298944124094 and 3298944124103.
It is not a weakly prime, because it can be changed into another prime (3298944127153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1649472062076 + 1649472062077.
It is an arithmetic number, because the mean of its divisors is an integer number (1649472062077).
Almost surely, 23298944124153 is an apocalyptic number.
It is an amenable number.
3298944124153 is a deficient number, since it is larger than the sum of its proper divisors (1).
3298944124153 is an equidigital number, since it uses as much as digits as its factorization.
3298944124153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7464960, while the sum is 55.
The spelling of 3298944124153 in words is "three trillion, two hundred ninety-eight billion, nine hundred forty-four million, one hundred twenty-four thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •