330002311131133 has 4 divisors (see below), whose sum is σ = 330582280044060. Its totient is φ = 329422342218208.

The previous prime is 330002311131089. The next prime is 330002311131149. The reversal of 330002311131133 is 331131113200033.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 127436034605049 + 202566276526084 = 11288757^2 + 14232578^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-330002311131133 is a prime.

It is a super-2 number, since 2×330002311131133² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 330002311131098 and 330002311131107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (330002311132133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289984455610 + ... + 289984456747.

It is an arithmetic number, because the mean of its divisors is an integer number (82645570011015).

Almost surely, 2^{330002311131133} is an apocalyptic number.

It is an amenable number.

330002311131133 is a deficient number, since it is larger than the sum of its proper divisors (579968912927).

330002311131133 is an equidigital number, since it uses as much as digits as its factorization.

330002311131133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 579968912926.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 330002311131133 its reverse (331131113200033), we get a palindrome (661133424331166).

The spelling of 330002311131133 in words is "three hundred thirty trillion, two billion, three hundred eleven million, one hundred thirty-one thousand, one hundred thirty-three".