Base | Representation |
---|---|
bin | 1100010010110100… |
… | …0000000100101001 |
3 | 22111222210000211021 |
4 | 3010231000010221 |
5 | 23224313143423 |
6 | 1303245132441 |
7 | 144531436336 |
oct | 30455000451 |
9 | 8458700737 |
10 | 3300131113 |
11 | 1443924394 |
12 | 78125a121 |
13 | 407929c06 |
14 | 23441198d |
15 | 144acb95d |
hex | c4b40129 |
3300131113 has 2 divisors, whose sum is σ = 3300131114. Its totient is φ = 3300131112.
The previous prime is 3300131099. The next prime is 3300131141. The reversal of 3300131113 is 3111310033.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3185812249 + 114318864 = 56443^2 + 10692^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3300131113 is a prime.
It is not a weakly prime, because it can be changed into another prime (3300138113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1650065556 + 1650065557.
It is an arithmetic number, because the mean of its divisors is an integer number (1650065557).
Almost surely, 23300131113 is an apocalyptic number.
It is an amenable number.
3300131113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3300131113 is an equidigital number, since it uses as much as digits as its factorization.
3300131113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 16.
The square root of 3300131113 is about 57446.7676462305. The cubic root of 3300131113 is about 1488.8252700424.
Adding to 3300131113 its reverse (3111310033), we get a palindrome (6411441146).
The spelling of 3300131113 in words is "three billion, three hundred million, one hundred thirty-one thousand, one hundred thirteen".
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