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330031221311249 is a prime number
BaseRepresentation
bin100101100001010010110000…
…1101101100000011100010001
31121021112200021021001021210022
41023002211201231200130101
5321224212420123424444
63125530130000313225
7126341653220013323
oct11302454155403421
91537480237037708
10330031221311249
1196181500596847
1231022318312815
131121ca6cc52823
145b6d84c507613
152824d095ab9ee
hex12c2961b60711

330031221311249 has 2 divisors, whose sum is σ = 330031221311250. Its totient is φ = 330031221311248.

The previous prime is 330031221311213. The next prime is 330031221311263. The reversal of 330031221311249 is 942113122130033.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 196982909203600 + 133048312107649 = 14035060^2 + 11534657^2 .

It is a cyclic number.

It is not a de Polignac number, because 330031221311249 - 220 = 330031220262673 is a prime.

It is a super-2 number, since 2×3300312213112492 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (330031221371249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165015610655624 + 165015610655625.

It is an arithmetic number, because the mean of its divisors is an integer number (165015610655625).

Almost surely, 2330031221311249 is an apocalyptic number.

It is an amenable number.

330031221311249 is a deficient number, since it is larger than the sum of its proper divisors (1).

330031221311249 is an equidigital number, since it uses as much as digits as its factorization.

330031221311249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 35.

The spelling of 330031221311249 in words is "three hundred thirty trillion, thirty-one billion, two hundred twenty-one million, three hundred eleven thousand, two hundred forty-nine".