Base | Representation |
---|---|
bin | 100101100001010100000100… |
… | …1000111110011100100010011 |
3 | 1121021112221112000002110222112 |
4 | 1023002220021013303210103 |
5 | 321224234143140003103 |
6 | 3125531312412255535 |
7 | 126342112633331411 |
oct | 11302501107634423 |
9 | 1537487460073875 |
10 | 330034030000403 |
11 | 96182711a69553 |
12 | 31022980a715ab |
13 | 112200c9b02a81 |
14 | 5b6da375502b1 |
15 | 2824e20e60cd8 |
hex | 12c2a091f3913 |
330034030000403 has 2 divisors, whose sum is σ = 330034030000404. Its totient is φ = 330034030000402.
The previous prime is 330034030000373. The next prime is 330034030000469. The reversal of 330034030000403 is 304000030430033.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 330034030000403 - 234 = 330016850131219 is a prime.
It is not a weakly prime, because it can be changed into another prime (330034030005403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165017015000201 + 165017015000202.
It is an arithmetic number, because the mean of its divisors is an integer number (165017015000202).
Almost surely, 2330034030000403 is an apocalyptic number.
330034030000403 is a deficient number, since it is larger than the sum of its proper divisors (1).
330034030000403 is an equidigital number, since it uses as much as digits as its factorization.
330034030000403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 23.
Adding to 330034030000403 its reverse (304000030430033), we get a palindrome (634034060430436).
The spelling of 330034030000403 in words is "three hundred thirty trillion, thirty-four billion, thirty million, four hundred three", and thus it is an aban number.
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