Base | Representation |
---|---|
bin | 110000000001101111110… |
… | …001000001001010000111 |
3 | 102200111221020200200002101 |
4 | 300001233301001022013 |
5 | 413033214430112403 |
6 | 11004104252252531 |
7 | 460306144105612 |
oct | 60015761011207 |
9 | 12614836620071 |
10 | 3300410004103 |
11 | 1062772451143 |
12 | 453784771147 |
13 | 1ac2c5593794 |
14 | b5a52685179 |
15 | 5acb7de071d |
hex | 3006fc41287 |
3300410004103 has 4 divisors (see below), whose sum is σ = 3370631493600. Its totient is φ = 3230188514608.
The previous prime is 3300410004041. The next prime is 3300410004173. The reversal of 3300410004103 is 3014000140033.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3300410004103 - 29 = 3300410003591 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3300410004173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35110744678 + ... + 35110744771.
It is an arithmetic number, because the mean of its divisors is an integer number (842657873400).
Almost surely, 23300410004103 is an apocalyptic number.
3300410004103 is a deficient number, since it is larger than the sum of its proper divisors (70221489497).
3300410004103 is an equidigital number, since it uses as much as digits as its factorization.
3300410004103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70221489496.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 3300410004103 its reverse (3014000140033), we get a palindrome (6314410144136).
The spelling of 3300410004103 in words is "three trillion, three hundred billion, four hundred ten million, four thousand, one hundred three".
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