Base | Representation |
---|---|
bin | 110000000001110000101… |
… | …100001110010100000001 |
3 | 102200111222022220012001012 |
4 | 300001300230032110001 |
5 | 413033232413240411 |
6 | 11004110005050305 |
7 | 460306423036541 |
oct | 60016054162401 |
9 | 12614868805035 |
10 | 3300425524481 |
11 | 10627801918a8 |
12 | 4537899b6995 |
13 | 1ac2c8868c37 |
14 | b5a54765321 |
15 | 5acb945918b |
hex | 30070b0e501 |
3300425524481 has 2 divisors, whose sum is σ = 3300425524482. Its totient is φ = 3300425524480.
The previous prime is 3300425524477. The next prime is 3300425524547. The reversal of 3300425524481 is 1844255240033.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3065790883600 + 234634640881 = 1750940^2 + 484391^2 .
It is a cyclic number.
It is not a de Polignac number, because 3300425524481 - 22 = 3300425524477 is a prime.
It is a super-2 number, since 2×33004255244812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3300425524421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1650212762240 + 1650212762241.
It is an arithmetic number, because the mean of its divisors is an integer number (1650212762241).
Almost surely, 23300425524481 is an apocalyptic number.
It is an amenable number.
3300425524481 is a deficient number, since it is larger than the sum of its proper divisors (1).
3300425524481 is an equidigital number, since it uses as much as digits as its factorization.
3300425524481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 460800, while the sum is 41.
The spelling of 3300425524481 in words is "three trillion, three hundred billion, four hundred twenty-five million, five hundred twenty-four thousand, four hundred eighty-one".
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