Base | Representation |
---|---|
bin | 11110101111100011… |
… | …001100111111010001 |
3 | 10011012112011100202020 |
4 | 132233203030333101 |
5 | 1020101030341423 |
6 | 23055315042053 |
7 | 2246006321241 |
oct | 365743147721 |
9 | 104175140666 |
10 | 33010012113 |
11 | 12aaa322751 |
12 | 6492ba0329 |
13 | 3160b73860 |
14 | 18520d9b21 |
15 | cd2ee94e3 |
hex | 7af8ccfd1 |
33010012113 has 32 divisors (see below), whose sum is σ = 47856506880. Its totient is φ = 20118067200.
The previous prime is 33010012109. The next prime is 33010012117. The reversal of 33010012113 is 31121001033.
It is an interprime number because it is at equal distance from previous prime (33010012109) and next prime (33010012117).
It is not a de Polignac number, because 33010012113 - 22 = 33010012109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 33010012092 and 33010012101.
It is not an unprimeable number, because it can be changed into a prime (33010012117) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7934928 + ... + 7939086.
It is an arithmetic number, because the mean of its divisors is an integer number (1495515840).
Almost surely, 233010012113 is an apocalyptic number.
It is an amenable number.
33010012113 is a deficient number, since it is larger than the sum of its proper divisors (14846494767).
33010012113 is a wasteful number, since it uses less digits than its factorization.
33010012113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6089.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 33010012113 its reverse (31121001033), we get a palindrome (64131013146).
The spelling of 33010012113 in words is "thirty-three billion, ten million, twelve thousand, one hundred thirteen".
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