Base | Representation |
---|---|
bin | 110000000010010011001… |
… | …100011101110101111001 |
3 | 102200120110200011012202211 |
4 | 300002103030131311321 |
5 | 413040424111331131 |
6 | 11004243244255121 |
7 | 460326652313323 |
oct | 60022314356571 |
9 | 12616420135684 |
10 | 3301004402041 |
11 | 1062a47a23105 |
12 | 45390b8414a1 |
13 | 1ac38b77a538 |
14 | b5aab5b0613 |
15 | 5ad001a35b1 |
hex | 3009331dd79 |
3301004402041 has 2 divisors, whose sum is σ = 3301004402042. Its totient is φ = 3301004402040.
The previous prime is 3301004401997. The next prime is 3301004402083. The reversal of 3301004402041 is 1402044001033.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2005268405625 + 1295735996416 = 1416075^2 + 1138304^2 .
It is a cyclic number.
It is not a de Polignac number, because 3301004402041 - 29 = 3301004401529 is a prime.
It is not a weakly prime, because it can be changed into another prime (3301004402441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1650502201020 + 1650502201021.
It is an arithmetic number, because the mean of its divisors is an integer number (1650502201021).
Almost surely, 23301004402041 is an apocalyptic number.
It is an amenable number.
3301004402041 is a deficient number, since it is larger than the sum of its proper divisors (1).
3301004402041 is an equidigital number, since it uses as much as digits as its factorization.
3301004402041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 3301004402041 its reverse (1402044001033), we get a palindrome (4703048403074).
The spelling of 3301004402041 in words is "three trillion, three hundred one billion, four million, four hundred two thousand, forty-one".
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