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3301112745433 is a prime number
BaseRepresentation
bin110000000010011001101…
…001110000110111011001
3102200120202020000121222001
4300002121221300313121
5413041134330323213
611004302114401001
7460332436235266
oct60023151606731
912616666017861
103301112745433
111062aa30a30a8
1245393bb90161
131ac3a8052859
14b5abbb3426d
155ad099551dd
hex30099a70dd9

3301112745433 has 2 divisors, whose sum is σ = 3301112745434. Its totient is φ = 3301112745432.

The previous prime is 3301112745397. The next prime is 3301112745479. The reversal of 3301112745433 is 3345472111033.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2664951771024 + 636160974409 = 1632468^2 + 797597^2 .

It is a cyclic number.

It is not a de Polignac number, because 3301112745433 - 29 = 3301112744921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3301112745392 and 3301112745401.

It is not a weakly prime, because it can be changed into another prime (3301212745433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1650556372716 + 1650556372717.

It is an arithmetic number, because the mean of its divisors is an integer number (1650556372717).

Almost surely, 23301112745433 is an apocalyptic number.

It is an amenable number.

3301112745433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3301112745433 is an equidigital number, since it uses as much as digits as its factorization.

3301112745433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90720, while the sum is 37.

Adding to 3301112745433 its reverse (3345472111033), we get a palindrome (6646584856466).

The spelling of 3301112745433 in words is "three trillion, three hundred one billion, one hundred twelve million, seven hundred forty-five thousand, four hundred thirty-three".