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330113122202993 is a prime number
BaseRepresentation
bin100101100001111000111001…
…1011000100111010101110001
31121021211111200002000200001012
41023003301303120213111301
5321232033133240443433
63130031512540520305
7126350612623060343
oct11303616330472561
91537744602020035
10330113122202993
11962032094a7a38
1231036174850095
13112276c2b4104c
145b737bb8dd293
152826eee8b2848
hex12c3c73627571

330113122202993 has 2 divisors, whose sum is σ = 330113122202994. Its totient is φ = 330113122202992.

The previous prime is 330113122202893. The next prime is 330113122203049. The reversal of 330113122202993 is 399202221311033.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 311533513697344 + 18579608505649 = 17650312^2 + 4310407^2 .

It is a cyclic number.

It is not a de Polignac number, because 330113122202993 - 220 = 330113121154417 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 330113122202993.

It is not a weakly prime, because it can be changed into another prime (330113122202293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165056561101496 + 165056561101497.

It is an arithmetic number, because the mean of its divisors is an integer number (165056561101497).

Almost surely, 2330113122202993 is an apocalyptic number.

It is an amenable number.

330113122202993 is a deficient number, since it is larger than the sum of its proper divisors (1).

330113122202993 is an equidigital number, since it uses as much as digits as its factorization.

330113122202993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 104976, while the sum is 41.

The spelling of 330113122202993 in words is "three hundred thirty trillion, one hundred thirteen billion, one hundred twenty-two million, two hundred two thousand, nine hundred ninety-three".