Base | Representation |
---|---|
bin | 100101100011010101100100… |
… | …1010100010100100001100101 |
3 | 1121022112112100102211211200000 |
4 | 1023012223021110110201211 |
5 | 321243313221344213131 |
6 | 3130303144312211513 |
7 | 126401156365000665 |
oct | 11306531124244145 |
9 | 1538475312754600 |
10 | 330312132413541 |
11 | 9627a652589723 |
12 | 31068854999b99 |
13 | 112403ba089695 |
14 | 5b7d29a3701a5 |
15 | 282c29aec0ce6 |
hex | 12c6ac9514865 |
330312132413541 has 24 divisors (see below), whose sum is σ = 506856557311104. Its totient is φ = 214837159286880.
The previous prime is 330312132413401. The next prime is 330312132413617. The reversal of 330312132413541 is 145314231213033.
330312132413541 is a `hidden beast` number, since 3 + 3 + 0 + 312 + 1 + 324 + 13 + 5 + 4 + 1 = 666.
It is not a de Polignac number, because 330312132413541 - 211 = 330312132411493 is a prime.
It is a super-2 number, since 2×3303121324135412 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 330312132413496 and 330312132413505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (330312132413941) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16576931341 + ... + 16576951266.
It is an arithmetic number, because the mean of its divisors is an integer number (21119023221296).
Almost surely, 2330312132413541 is an apocalyptic number.
It is an amenable number.
330312132413541 is a deficient number, since it is larger than the sum of its proper divisors (176544424897563).
330312132413541 is an equidigital number, since it uses as much as digits as its factorization.
330312132413541 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33153882663 (or 33153882651 counting only the distinct ones).
The product of its (nonzero) digits is 77760, while the sum is 36.
Adding to 330312132413541 its reverse (145314231213033), we get a palindrome (475626363626574).
The spelling of 330312132413541 in words is "three hundred thirty trillion, three hundred twelve billion, one hundred thirty-two million, four hundred thirteen thousand, five hundred forty-one".
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