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33040311133 = 142323218771
BaseRepresentation
bin11110110001010110…
…110010001101011101
310011021122011201012011
4132301112302031131
51020131304424013
623102320311221
72246525003464
oct366126621535
9104248151164
1033040311133
1113015437865
1264a1172511
13316722197b
1418561459db
15cd59d1c3d
hex7b15b235d

33040311133 has 4 divisors (see below), whose sum is σ = 33063531328. Its totient is φ = 33017090940.

The previous prime is 33040311119. The next prime is 33040311137. The reversal of 33040311133 is 33111304033.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 33040311133 - 213 = 33040302941 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (33040311137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11607963 + ... + 11610808.

It is an arithmetic number, because the mean of its divisors is an integer number (8265882832).

Almost surely, 233040311133 is an apocalyptic number.

It is an amenable number.

33040311133 is a deficient number, since it is larger than the sum of its proper divisors (23220195).

33040311133 is a wasteful number, since it uses less digits than its factorization.

33040311133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23220194.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 33040311133 its reverse (33111304033), we get a palindrome (66151615166).

The spelling of 33040311133 in words is "thirty-three billion, forty million, three hundred eleven thousand, one hundred thirty-three".

Divisors: 1 1423 23218771 33040311133