Base | Representation |
---|---|
bin | 1111000001100110100110… |
… | …01010010100110010101011 |
3 | 11022222122010110021202100021 |
4 | 13200303103022110302223 |
5 | 13312313300332440021 |
6 | 154134321534221311 |
7 | 6650043453563131 |
oct | 740632312246253 |
9 | 138878113252307 |
10 | 33040431140011 |
11 | a58940601a729 |
12 | 3857559654837 |
13 | 1558912446b29 |
14 | 823245bdd751 |
15 | 3c46cdcb9c41 |
hex | 1e0cd3294cab |
33040431140011 has 4 divisors (see below), whose sum is σ = 33040465328952. Its totient is φ = 33040396951072.
The previous prime is 33040431139999. The next prime is 33040431140089. The reversal of 33040431140011 is 11004113404033.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 33040431140011 - 225 = 33040397585579 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (33040431146011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15601390 + ... + 17592163.
It is an arithmetic number, because the mean of its divisors is an integer number (8260116332238).
Almost surely, 233040431140011 is an apocalyptic number.
33040431140011 is a deficient number, since it is larger than the sum of its proper divisors (34188941).
33040431140011 is an equidigital number, since it uses as much as digits as its factorization.
33040431140011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34188940.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 33040431140011 its reverse (11004113404033), we get a palindrome (44044544544044).
The spelling of 33040431140011 in words is "thirty-three trillion, forty billion, four hundred thirty-one million, one hundred forty thousand, eleven".
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