Base | Representation |
---|---|
bin | 110000000101011010010… |
… | …000001011001010100001 |
3 | 102200220002102021101221012 |
4 | 300011122100023022201 |
5 | 413114244033240342 |
6 | 11005554504310305 |
7 | 460505503625402 |
oct | 60053220131241 |
9 | 12626072241835 |
10 | 3304344040097 |
11 | 1064401080661 |
12 | 4544a2172395 |
13 | 1ac7a162a729 |
14 | b5d06d479a9 |
15 | 5ae48485b82 |
hex | 3015a40b2a1 |
3304344040097 has 2 divisors, whose sum is σ = 3304344040098. Its totient is φ = 3304344040096.
The previous prime is 3304344040079. The next prime is 3304344040103. The reversal of 3304344040097 is 7900404434033.
Together with previous prime (3304344040079) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2851366582801 + 452977457296 = 1688599^2 + 673036^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3304344040097 is a prime.
It is not a weakly prime, because it can be changed into another prime (3304344060097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1652172020048 + 1652172020049.
It is an arithmetic number, because the mean of its divisors is an integer number (1652172020049).
Almost surely, 23304344040097 is an apocalyptic number.
It is an amenable number.
3304344040097 is a deficient number, since it is larger than the sum of its proper divisors (1).
3304344040097 is an equidigital number, since it uses as much as digits as its factorization.
3304344040097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 435456, while the sum is 41.
The spelling of 3304344040097 in words is "three trillion, three hundred four billion, three hundred forty-four million, forty thousand, ninety-seven".
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