Base | Representation |
---|---|
bin | 1111000001111110000000… |
… | …11110000000001101000001 |
3 | 11100000211120120101121211002 |
4 | 13200333000132000031001 |
5 | 13313020022110331340 |
6 | 154144201212501345 |
7 | 6651000133035116 |
oct | 740770036001501 |
9 | 140024516347732 |
10 | 33053002433345 |
11 | a593777202454 |
12 | 3859a8777a855 |
13 | 1559b66a65b3b |
14 | 823ab965090d |
15 | 3c4bb7787715 |
hex | 1e0fc0780341 |
33053002433345 has 32 divisors (see below), whose sum is σ = 42237211919616. Its totient is φ = 24744762419200.
The previous prime is 33053002433317. The next prime is 33053002433377. The reversal of 33053002433345 is 54333420035033.
It is not a de Polignac number, because 33053002433345 - 218 = 33053002171201 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 33053002433299 and 33053002433308.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13557980 + ... + 15809010.
It is an arithmetic number, because the mean of its divisors is an integer number (1319912872488).
Almost surely, 233053002433345 is an apocalyptic number.
It is an amenable number.
33053002433345 is a deficient number, since it is larger than the sum of its proper divisors (9184209486271).
33053002433345 is a wasteful number, since it uses less digits than its factorization.
33053002433345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2252041.
The product of its (nonzero) digits is 583200, while the sum is 38.
Adding to 33053002433345 its reverse (54333420035033), we get a palindrome (87386422468378).
The spelling of 33053002433345 in words is "thirty-three trillion, fifty-three billion, two million, four hundred thirty-three thousand, three hundred forty-five".
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