Base | Representation |
---|---|
bin | 110000000110010011111… |
… | …101100111100001011011 |
3 | 102200222120220010202202222 |
4 | 300012103331213201123 |
5 | 413123234414112133 |
6 | 11010234532414255 |
7 | 460541501411522 |
oct | 60062375474133 |
9 | 12628526122688 |
10 | 3305312254043 |
11 | 1064858664078 |
12 | 45471247738b |
13 | 1ac8c70b89a7 |
14 | b5d9977d4b9 |
15 | 5aea3488e98 |
hex | 30193f6785b |
3305312254043 has 2 divisors, whose sum is σ = 3305312254044. Its totient is φ = 3305312254042.
The previous prime is 3305312254019. The next prime is 3305312254103. The reversal of 3305312254043 is 3404522135033.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3305312254043 - 212 = 3305312249947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3305312253994 and 3305312254012.
It is not a weakly prime, because it can be changed into another prime (3301312254043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1652656127021 + 1652656127022.
It is an arithmetic number, because the mean of its divisors is an integer number (1652656127022).
Almost surely, 23305312254043 is an apocalyptic number.
3305312254043 is a deficient number, since it is larger than the sum of its proper divisors (1).
3305312254043 is an equidigital number, since it uses as much as digits as its factorization.
3305312254043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 3305312254043 its reverse (3404522135033), we get a palindrome (6709834389076).
The spelling of 3305312254043 in words is "three trillion, three hundred five billion, three hundred twelve million, two hundred fifty-four thousand, forty-three".
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